Current Sensor Carrier 0A-30A ACS724

 This version accepts a unidirectional current input up to 30 A and outputs a proportional analog voltage (133 mV/A) that measures 500 mV when the input current is zero. The typical output error is ±1.5%. It operates from 4.5 V to 5.5 V and is intended for use in 5 V systems.

Overview

This current sensor is a carrier board or breakout board for Allegro’s ACS715LLCTR-30A-T Hall effect-based linear current sensor; we therefore recommend careful reading of the ACS715 datasheet (589k pdf) before using this product. The sensor operates at 5 V and has an output sensitivity of 133 mV/A. The board ships fully populated with its SMD components, including the ACS715, as shown in the product picture. The following list details some of the sensor’s key features:

• Designed for unidirectional input current from 0 to 30 A, but the sensor will provide meaningful feedback for currents as low as -1.5 A, and the robust IC can survive up to five times the overcurrent condition.
• Conductive path internal resistance is typically 1.2 mΩ, and the PCB is made with 2-oz copper, so very little power is lost in the board.
• Use of a Hall effect sensor means the IC is able to electrically isolate the current path from the sensor’s electronics (up to 2.1 kV RMS), which allows the sensor to be inserted anywhere along the current path and to be used in applications that require electrical isolation.
• 80 kHz bandwidth that can optionally be decreased by adding a capacitor across the board pins marked “filter”.
• High accuracy and reliability: typical total output error of ±1.5% at room temperature with factory calibration, an extremely stable output offset voltage, and almost zero magnetic hysteresis.
• Automotive-grade operating temperature range of -40°C to 150°C.

The pads are labeled on the bottom silkscreen, as shown in the picture to the right. The silkscreen also shows the direction that is interpreted as positive current flow via the +i arrow.

This version is marked with a black X. We also sell a ±5A bidirectional version and a ±30A bidirectional version of this board; you can distinguish these versions by reading the text on the IC or by looking at the color of the X on the bottom silkscreen.

Using the sensor

ACS715 current sensor carrier with solderless ring terminal connectors (not included).

Electrical connections
The sensor requires a supply voltage of 4.5 V to 5.5 V to be connected across the Vcc and GND pads, which are labeled on the bottom silkscreen. The sensor outputs an analog voltage that is linearly proportional to the input current. When Vcc is 5 V, this output voltage is offset by 500 mV and increases by 133 mV per amp of input current. The output voltage decreases linearly below 500 mV for currents as low as -1.5 A.

Warning: This product is intended for use below 30 V. Working with higher voltages can be extremely dangerous and should only be attempted by qualified individuals with appropriate equipment and protective gear.

The input current can be connected to the board in a variety of ways. For low-current applications, you can solder 0.1" male header pins to the board via the small through-holes on the input-current side of the board. For higher-current applications, you can solder wires directly to the through-holes whose sizes best match your wires, or you can use solderless ring terminal connectors, as shown in the picture to the right. The large through-holes are big enough for #6 screws.

Mounting information
The board has two mounting holes on the logic side of the board. These mounting holes are 0.5" apart and are designed for #2 screws.

Filtering the output
The IC has an internal filter resistance of 1.7 kΩ, and the carrier board includes a 1 nF filter capacitor, which produces a low-pass RC filter with a 90 kHz cutoff. You can improve sensing system accuracy for low-frequency sensing applictations by adding a capacitor in parallel with the integrated 1 nF capacitor across the pads marked “filter” on the bottom silkscreen (this capacitor is labeled C2b in the schematic below). The frequency F that the filter will attenuate to half its original power is given by:

F = 1 / (2πRC) = 1 / (11kΩ * (1 nF + Cf))

where Cf is the value of the capacitor added to the filter pads.